2[x-3(y-x)+3]=-22

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Solution for 2[x-3(y-x)+3]=-22 equation: 


Simplifying
2[x + -3(y + -1x) + 3] = -22

Reorder the terms:
2[x + -3(-1x + y) + 3] = -22
2[x + (-1x * -3 + y * -3) + 3] = -22
2[x + (3x + -3y) + 3] = -22

Reorder the terms:
2[3 + x + 3x + -3y] = -22

Combine like terms: x + 3x = 4x
2[3 + 4x + -3y] = -22
[3 * 2 + 4x * 2 + -3y * 2] = -22
[6 + 8x + -6y] = -22

Solving
6 + 8x + -6y = -22

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 8x + -6 + -6y = -22 + -6

Reorder the terms:
6 + -6 + 8x + -6y = -22 + -6

Combine like terms: 6 + -6 = 0
0 + 8x + -6y = -22 + -6
8x + -6y = -22 + -6

Combine like terms: -22 + -6 = -28
8x + -6y = -28

Add '6y' to each side of the equation.
8x + -6y + 6y = -28 + 6y

Combine like terms: -6y + 6y = 0
8x + 0 = -28 + 6y
8x = -28 + 6y

Divide each side by '8'.
x = -3.5 + 0.75y

Simplifying
x = -3.5 + 0.75y

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